-5(-3y+1)-7y=2(y-1)-1

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Solution for -5(-3y+1)-7y=2(y-1)-1 equation: 



-5(-3y+1)-7y=2(y-1)-1

We move all terms to the left:

-5(-3y+1)-7y-(2(y-1)-1)=0

We add all the numbers together, and all the variables

-7y-5(-3y+1)-(2(y-1)-1)=0

We multiply parentheses

-7y+15y-(2(y-1)-1)-5=0



We calculate terms in parentheses: -(2(y-1)-1), so:

2(y-1)-1

We multiply parentheses

2y-2-1

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)



We add all the numbers together, and all the variables

8y-(2y-3)-5=0

We get rid of parentheses

8y-2y+3-5=0

We add all the numbers together, and all the variables

6y-2=0

We move all terms containing y to the left, all other terms to the right

6y=2

y=2/6

y=1/3

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