-5(-3y+2)-2y=3(y-8)-4

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Solution for -5(-3y+2)-2y=3(y-8)-4 equation: 



-5(-3y+2)-2y=3(y-8)-4

We move all terms to the left:

-5(-3y+2)-2y-(3(y-8)-4)=0

We add all the numbers together, and all the variables

-2y-5(-3y+2)-(3(y-8)-4)=0

We multiply parentheses

-2y+15y-(3(y-8)-4)-10=0



We calculate terms in parentheses: -(3(y-8)-4), so:

3(y-8)-4

We multiply parentheses

3y-24-4

We add all the numbers together, and all the variables

3y-28

Back to the equation:

-(3y-28)



We add all the numbers together, and all the variables

13y-(3y-28)-10=0

We get rid of parentheses

13y-3y+28-10=0

We add all the numbers together, and all the variables

10y+18=0

We move all terms containing y to the left, all other terms to the right

10y=-18

y=-18/10

y=-1+4/5

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