-5(-3y+3)-3y=3(y-2)-3

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Solution for -5(-3y+3)-3y=3(y-2)-3 equation: 



-5(-3y+3)-3y=3(y-2)-3

We move all terms to the left:

-5(-3y+3)-3y-(3(y-2)-3)=0

We add all the numbers together, and all the variables

-3y-5(-3y+3)-(3(y-2)-3)=0

We multiply parentheses

-3y+15y-(3(y-2)-3)-15=0



We calculate terms in parentheses: -(3(y-2)-3), so:

3(y-2)-3

We multiply parentheses

3y-6-3

We add all the numbers together, and all the variables

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

12y-(3y-9)-15=0

We get rid of parentheses

12y-3y+9-15=0

We add all the numbers together, and all the variables

9y-6=0

We move all terms containing y to the left, all other terms to the right

9y=6

y=6/9

y=2/3

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