-5(-3y+3)-3y=y(-2)-3

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Solution for -5(-3y+3)-3y=y(-2)-3 equation: 



-5(-3y+3)-3y=y(-2)-3

We move all terms to the left:

-5(-3y+3)-3y-(y(-2)-3)=0

We add all the numbers together, and all the variables

-3y-5(-3y+3)-(y(-2)-3)=0

We multiply parentheses

-3y+15y-(y(-2)-3)-15=0



We calculate terms in parentheses: -(y(-2)-3), so:

y(-2)-3

We multiply parentheses

-2y-3

Back to the equation:

-(-2y-3)



We add all the numbers together, and all the variables

12y-(-2y-3)-15=0

We get rid of parentheses

12y+2y+3-15=0

We add all the numbers together, and all the variables

14y-12=0

We move all terms containing y to the left, all other terms to the right

14y=12

y=12/14

y=6/7

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