-5(-4u+2)-6u=2(u-5)-6

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Solution for -5(-4u+2)-6u=2(u-5)-6 equation:



-5(-4u+2)-6u=2(u-5)-6
We move all terms to the left:
-5(-4u+2)-6u-(2(u-5)-6)=0
We add all the numbers together, and all the variables
-6u-5(-4u+2)-(2(u-5)-6)=0
We multiply parentheses
-6u+20u-(2(u-5)-6)-10=0
We calculate terms in parentheses: -(2(u-5)-6), so:
2(u-5)-6
We multiply parentheses
2u-10-6
We add all the numbers together, and all the variables
2u-16
Back to the equation:
-(2u-16)
We add all the numbers together, and all the variables
14u-(2u-16)-10=0
We get rid of parentheses
14u-2u+16-10=0
We add all the numbers together, and all the variables
12u+6=0
We move all terms containing u to the left, all other terms to the right
12u=-6
u=-6/12
u=-1/2

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