-5(-4u+5)-4u=4(u-2)-1

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Solution for -5(-4u+5)-4u=4(u-2)-1 equation: 



-5(-4u+5)-4u=4(u-2)-1

We move all terms to the left:

-5(-4u+5)-4u-(4(u-2)-1)=0

We add all the numbers together, and all the variables

-4u-5(-4u+5)-(4(u-2)-1)=0

We multiply parentheses

-4u+20u-(4(u-2)-1)-25=0



We calculate terms in parentheses: -(4(u-2)-1), so:

4(u-2)-1

We multiply parentheses

4u-8-1

We add all the numbers together, and all the variables

4u-9

Back to the equation:

-(4u-9)



We add all the numbers together, and all the variables

16u-(4u-9)-25=0

We get rid of parentheses

16u-4u+9-25=0

We add all the numbers together, and all the variables

12u-16=0

We move all terms containing u to the left, all other terms to the right

12u=16

u=16/12

u=1+1/3

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