-5(-5y+3)-7y=3(y-4)-6

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Solution for -5(-5y+3)-7y=3(y-4)-6 equation: 



-5(-5y+3)-7y=3(y-4)-6

We move all terms to the left:

-5(-5y+3)-7y-(3(y-4)-6)=0

We add all the numbers together, and all the variables

-7y-5(-5y+3)-(3(y-4)-6)=0

We multiply parentheses

-7y+25y-(3(y-4)-6)-15=0



We calculate terms in parentheses: -(3(y-4)-6), so:

3(y-4)-6

We multiply parentheses

3y-12-6

We add all the numbers together, and all the variables

3y-18

Back to the equation:

-(3y-18)



We add all the numbers together, and all the variables

18y-(3y-18)-15=0

We get rid of parentheses

18y-3y+18-15=0

We add all the numbers together, and all the variables

15y+3=0

We move all terms containing y to the left, all other terms to the right

15y=-3

y=-3/15

y=-1/5

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