-5(1+x)+x=-3(6+2x)+6

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Solution for -5(1+x)+x=-3(6+2x)+6 equation: 



-5(1+x)+x=-3(6+2x)+6

We move all terms to the left:

-5(1+x)+x-(-3(6+2x)+6)=0

We add all the numbers together, and all the variables

-5(x+1)+x-(-3(2x+6)+6)=0

We add all the numbers together, and all the variables

x-5(x+1)-(-3(2x+6)+6)=0

We multiply parentheses

x-5x-(-3(2x+6)+6)-5=0



We calculate terms in parentheses: -(-3(2x+6)+6), so:

-3(2x+6)+6

We multiply parentheses

-6x-18+6

We add all the numbers together, and all the variables

-6x-12

Back to the equation:

-(-6x-12)



We add all the numbers together, and all the variables

-4x-(-6x-12)-5=0

We get rid of parentheses

-4x+6x+12-5=0

We add all the numbers together, and all the variables

2x+7=0

We move all terms containing x to the left, all other terms to the right

2x=-7

x=-7/2

x=-3+1/2

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