-5(1-2v)=9(v-2)

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Solution for -5(1-2v)=9(v-2) equation:



-5(1-2v)=9(v-2)
We move all terms to the left:
-5(1-2v)-(9(v-2))=0
We add all the numbers together, and all the variables
-5(-2v+1)-(9(v-2))=0
We multiply parentheses
10v-(9(v-2))-5=0
We calculate terms in parentheses: -(9(v-2)), so:
9(v-2)
We multiply parentheses
9v-18
Back to the equation:
-(9v-18)
We get rid of parentheses
10v-9v+18-5=0
We add all the numbers together, and all the variables
v+13=0
We move all terms containing v to the left, all other terms to the right
v=-13

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