-5(1-3n)=4n+4(2n-4)

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Solution for -5(1-3n)=4n+4(2n-4) equation:



-5(1-3n)=4n+4(2n-4)
We move all terms to the left:
-5(1-3n)-(4n+4(2n-4))=0
We add all the numbers together, and all the variables
-5(-3n+1)-(4n+4(2n-4))=0
We multiply parentheses
15n-(4n+4(2n-4))-5=0
We calculate terms in parentheses: -(4n+4(2n-4)), so:
4n+4(2n-4)
We multiply parentheses
4n+8n-16
We add all the numbers together, and all the variables
12n-16
Back to the equation:
-(12n-16)
We get rid of parentheses
15n-12n+16-5=0
We add all the numbers together, and all the variables
3n+11=0
We move all terms containing n to the left, all other terms to the right
3n=-11
n=-11/3
n=-3+2/3

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