-5(1-3x)=2(8x+1)-1

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Solution for -5(1-3x)=2(8x+1)-1 equation: 



-5(1-3x)=2(8x+1)-1

We move all terms to the left:

-5(1-3x)-(2(8x+1)-1)=0

We add all the numbers together, and all the variables

-5(-3x+1)-(2(8x+1)-1)=0

We multiply parentheses

15x-(2(8x+1)-1)-5=0



We calculate terms in parentheses: -(2(8x+1)-1), so:

2(8x+1)-1

We multiply parentheses

16x+2-1

We add all the numbers together, and all the variables

16x+1

Back to the equation:

-(16x+1)



We get rid of parentheses

15x-16x-1-5=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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