-5(1-3x)=4(3-x)+2

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Solution for -5(1-3x)=4(3-x)+2 equation: 



-5(1-3x)=4(3-x)+2

We move all terms to the left:

-5(1-3x)-(4(3-x)+2)=0

We add all the numbers together, and all the variables

-5(-3x+1)-(4(-1x+3)+2)=0

We multiply parentheses

15x-(4(-1x+3)+2)-5=0



We calculate terms in parentheses: -(4(-1x+3)+2), so:

4(-1x+3)+2

We multiply parentheses

-4x+12+2

We add all the numbers together, and all the variables

-4x+14

Back to the equation:

-(-4x+14)



We get rid of parentheses

15x+4x-14-5=0

We add all the numbers together, and all the variables

19x-19=0

We move all terms containing x to the left, all other terms to the right

19x=19

x=19/19

x=1

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