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-5(1-5x)+5(-8x^2)=-4x-8x
We move all terms to the left:
-5(1-5x)+5(-8x^2)-(-4x-8x)=0
We add all the numbers together, and all the variables
5(-8x^2)-5(-5x+1)-(-12x)=0
We multiply parentheses
-40x^2+25x-(-12x)-5=0
We get rid of parentheses
-40x^2+25x+12x-5=0
We add all the numbers together, and all the variables
-40x^2+37x-5=0
a = -40; b = 37; c = -5;
Δ = b2-4ac
Δ = 372-4·(-40)·(-5)
Δ = 569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{569}}{2*-40}=\frac{-37-\sqrt{569}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{569}}{2*-40}=\frac{-37+\sqrt{569}}{-80} $
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