-5(1-5x)=-4x-8x-5(-8x-2)

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Solution for -5(1-5x)=-4x-8x-5(-8x-2) equation:



-5(1-5x)=-4x-8x-5(-8x-2)
We move all terms to the left:
-5(1-5x)-(-4x-8x-5(-8x-2))=0
We add all the numbers together, and all the variables
-5(-5x+1)-(-4x-8x-5(-8x-2))=0
We multiply parentheses
25x-(-4x-8x-5(-8x-2))-5=0
We calculate terms in parentheses: -(-4x-8x-5(-8x-2)), so:
-4x-8x-5(-8x-2)
We add all the numbers together, and all the variables
-12x-5(-8x-2)
We multiply parentheses
-12x+40x+10
We add all the numbers together, and all the variables
28x+10
Back to the equation:
-(28x+10)
We get rid of parentheses
25x-28x-10-5=0
We add all the numbers together, and all the variables
-3x-15=0
We move all terms containing x to the left, all other terms to the right
-3x=15
x=15/-3
x=-5

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