-5(1/6x-8)=40-x+1/6

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Solution for -5(1/6x-8)=40-x+1/6 equation: 



-5(1/6x-8)=40-x+1/6

We move all terms to the left:

-5(1/6x-8)-(40-x+1/6)=0



Domain of the equation: 6x-8)!=0

x∈R



We add all the numbers together, and all the variables

-5(1/6x-8)-(-1x+1/6+40)=0

We multiply parentheses

-5x-(-1x+1/6+40)+40=0

We get rid of parentheses

-5x+1x-40+40-1/6=0

We multiply all the terms by the denominator


-5x*6+1x*6-1-40*6+40*6=0

We add all the numbers together, and all the variables

-5x*6+1x*6-1=0

Wy multiply elements

-30x+6x-1=0

We add all the numbers together, and all the variables

-24x-1=0

We move all terms containing x to the left, all other terms to the right

-24x=1

x=1/-24

x=-1/24

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