-5(1/6x-8)=40-x+1/6x

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Solution for -5(1/6x-8)=40-x+1/6x equation:



-5(1/6x-8)=40-x+1/6x
We move all terms to the left:
-5(1/6x-8)-(40-x+1/6x)=0
Domain of the equation: 6x-8)!=0
x∈R
Domain of the equation: 6x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-5(1/6x-8)-(-1x+1/6x+40)=0
We multiply parentheses
-5x-(-1x+1/6x+40)+40=0
We get rid of parentheses
-5x+1x-1/6x-40+40=0
We multiply all the terms by the denominator
-5x*6x+1x*6x-40*6x+40*6x-1=0
Wy multiply elements
-30x^2+6x^2-240x+240x-1=0
We add all the numbers together, and all the variables
-24x^2-1=0
a = -24; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-24)·(-1)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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