-5(2-3y)-5(-5+2y)=140

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Solution for -5(2-3y)-5(-5+2y)=140 equation: 



-5(2-3y)-5(-5+2y)=140

We move all terms to the left:

-5(2-3y)-5(-5+2y)-(140)=0

We add all the numbers together, and all the variables

-5(-3y+2)-5(2y-5)-140=0

We multiply parentheses

15y-10y-10+25-140=0

We add all the numbers together, and all the variables

5y-125=0

We move all terms containing y to the left, all other terms to the right

5y=125

y=125/5

y=25

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