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-5(2/5x+2)=6
We move all terms to the left:
-5(2/5x+2)-(6)=0
Domain of the equation: 5x+2)!=0We multiply parentheses
x∈R
-10x-10-6=0
We add all the numbers together, and all the variables
-10x-16=0
We move all terms containing x to the left, all other terms to the right
-10x=16
x=16/-10
x=-1+3/5
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