-5(2b+1)+(11b-3)=0

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Solution for -5(2b+1)+(11b-3)=0 equation:


Simplifying
-5(2b + 1) + (11b + -3) = 0

Reorder the terms:
-5(1 + 2b) + (11b + -3) = 0
(1 * -5 + 2b * -5) + (11b + -3) = 0
(-5 + -10b) + (11b + -3) = 0

Reorder the terms:
-5 + -10b + (-3 + 11b) = 0

Remove parenthesis around (-3 + 11b)
-5 + -10b + -3 + 11b = 0

Reorder the terms:
-5 + -3 + -10b + 11b = 0

Combine like terms: -5 + -3 = -8
-8 + -10b + 11b = 0

Combine like terms: -10b + 11b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8

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