-5(2b+2)=-3b-5(b+10)

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Solution for -5(2b+2)=-3b-5(b+10) equation: 



-5(2b+2)=-3b-5(b+10)

We move all terms to the left:

-5(2b+2)-(-3b-5(b+10))=0

We multiply parentheses

-10b-(-3b-5(b+10))-10=0



We calculate terms in parentheses: -(-3b-5(b+10)), so:

-3b-5(b+10)

We multiply parentheses

-3b-5b-50

We add all the numbers together, and all the variables

-8b-50

Back to the equation:

-(-8b-50)



We get rid of parentheses

-10b+8b+50-10=0

We add all the numbers together, and all the variables

-2b+40=0

We move all terms containing b to the left, all other terms to the right

-2b=-40

b=-40/-2

b=+20

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