-5(2t-2)+7t=2t-7

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Solution for -5(2t-2)+7t=2t-7 equation: 



-5(2t-2)+7t=2t-7

We move all terms to the left:

-5(2t-2)+7t-(2t-7)=0

We add all the numbers together, and all the variables

7t-5(2t-2)-(2t-7)=0

We multiply parentheses

7t-10t-(2t-7)+10=0

We get rid of parentheses

7t-10t-2t+7+10=0

We add all the numbers together, and all the variables

-5t+17=0

We move all terms containing t to the left, all other terms to the right

-5t=-17

t=-17/-5

t=3+2/5

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