-5(2t-3)+2t=5t-2

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Solution for -5(2t-3)+2t=5t-2 equation: 



-5(2t-3)+2t=5t-2

We move all terms to the left:

-5(2t-3)+2t-(5t-2)=0

We add all the numbers together, and all the variables

2t-5(2t-3)-(5t-2)=0

We multiply parentheses

2t-10t-(5t-2)+15=0

We get rid of parentheses

2t-10t-5t+2+15=0

We add all the numbers together, and all the variables

-13t+17=0

We move all terms containing t to the left, all other terms to the right

-13t=-17

t=-17/-13

t=1+4/13

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