-5(2t-4)+3t=2t-2

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Solution for -5(2t-4)+3t=2t-2 equation: 



-5(2t-4)+3t=2t-2

We move all terms to the left:

-5(2t-4)+3t-(2t-2)=0

We add all the numbers together, and all the variables

3t-5(2t-4)-(2t-2)=0

We multiply parentheses

3t-10t-(2t-2)+20=0

We get rid of parentheses

3t-10t-2t+2+20=0

We add all the numbers together, and all the variables

-9t+22=0

We move all terms containing t to the left, all other terms to the right

-9t=-22

t=-22/-9

t=2+4/9

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