-5(2t-5)+2t=5t-2

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Solution for -5(2t-5)+2t=5t-2 equation:



-5(2t-5)+2t=5t-2
We move all terms to the left:
-5(2t-5)+2t-(5t-2)=0
We add all the numbers together, and all the variables
2t-5(2t-5)-(5t-2)=0
We multiply parentheses
2t-10t-(5t-2)+25=0
We get rid of parentheses
2t-10t-5t+2+25=0
We add all the numbers together, and all the variables
-13t+27=0
We move all terms containing t to the left, all other terms to the right
-13t=-27
t=-27/-13
t=2+1/13

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