-5(2t-5)+4t=5t-2

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Solution for -5(2t-5)+4t=5t-2 equation: 



-5(2t-5)+4t=5t-2

We move all terms to the left:

-5(2t-5)+4t-(5t-2)=0

We add all the numbers together, and all the variables

4t-5(2t-5)-(5t-2)=0

We multiply parentheses

4t-10t-(5t-2)+25=0

We get rid of parentheses

4t-10t-5t+2+25=0

We add all the numbers together, and all the variables

-11t+27=0

We move all terms containing t to the left, all other terms to the right

-11t=-27

t=-27/-11

t=2+5/11

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