-5(2u-1)+8u=1+2(5u-3)

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Solution for -5(2u-1)+8u=1+2(5u-3) equation: 



-5(2u-1)+8u=1+2(5u-3)

We move all terms to the left:

-5(2u-1)+8u-(1+2(5u-3))=0

We add all the numbers together, and all the variables

8u-5(2u-1)-(1+2(5u-3))=0

We multiply parentheses

8u-10u-(1+2(5u-3))+5=0



We calculate terms in parentheses: -(1+2(5u-3)), so:

1+2(5u-3)

determiningTheFunctionDomain
2(5u-3)+1

We multiply parentheses

10u-6+1

We add all the numbers together, and all the variables

10u-5

Back to the equation:

-(10u-5)



We add all the numbers together, and all the variables

-2u-(10u-5)+5=0

We get rid of parentheses

-2u-10u+5+5=0

We add all the numbers together, and all the variables

-12u+10=0

We move all terms containing u to the left, all other terms to the right

-12u=-10

u=-10/-12

u=5/6

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