-5(2v-3)+6v=9+2(2v-6)

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Solution for -5(2v-3)+6v=9+2(2v-6) equation: 



-5(2v-3)+6v=9+2(2v-6)

We move all terms to the left:

-5(2v-3)+6v-(9+2(2v-6))=0

We add all the numbers together, and all the variables

6v-5(2v-3)-(9+2(2v-6))=0

We multiply parentheses

6v-10v-(9+2(2v-6))+15=0



We calculate terms in parentheses: -(9+2(2v-6)), so:

9+2(2v-6)

determiningTheFunctionDomain
2(2v-6)+9

We multiply parentheses

4v-12+9

We add all the numbers together, and all the variables

4v-3

Back to the equation:

-(4v-3)



We add all the numbers together, and all the variables

-4v-(4v-3)+15=0

We get rid of parentheses

-4v-4v+3+15=0

We add all the numbers together, and all the variables

-8v+18=0

We move all terms containing v to the left, all other terms to the right

-8v=-18

v=-18/-8

v=2+1/4

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