-5(2w-4)+2w=6+2(3w-1)

Solution for -5(2w-4)+2w=6+2(3w-1) equation:

-5(2w-4)+2w=6+2(3w-1)

We move all terms to the left:

-5(2w-4)+2w-(6+2(3w-1))=0

We add all the numbers together, and all the variables

2w-5(2w-4)-(6+2(3w-1))=0

We multiply parentheses

2w-10w-(6+2(3w-1))+20=0


We calculate terms in parentheses: -(6+2(3w-1)), so:

6+2(3w-1)

determiningTheFunctionDomain
2(3w-1)+6

We multiply parentheses

6w-2+6

We add all the numbers together, and all the variables

6w+4

Back to the equation:

-(6w+4)


We add all the numbers together, and all the variables

-8w-(6w+4)+20=0

We get rid of parentheses

-8w-6w-4+20=0

We add all the numbers together, and all the variables

-14w+16=0

We move all terms containing w to the left, all other terms to the right

-14w=-16

w=-16/-14

w=1+1/7