-5(2x+1)=-3x(1+4x)

Solution for -5(2x+1)=-3x(1+4x) equation:

-5(2x+1)=-3x(1+4x)

We move all terms to the left:

-5(2x+1)-(-3x(1+4x))=0

We add all the numbers together, and all the variables

-5(2x+1)-(-3x(4x+1))=0

We multiply parentheses

-10x-(-3x(4x+1))-5=0


We calculate terms in parentheses: -(-3x(4x+1)), so:

-3x(4x+1)

We multiply parentheses

-12x^2-3x

Back to the equation:

-(-12x^2-3x)


We get rid of parentheses

12x^2+3x-10x-5=0

We add all the numbers together, and all the variables

12x^2-7x-5=0

a = 12; b = -7; c = -5;
Δ = b2-4ac
Δ = -72-4·12·(-5)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*12}=\frac{-10}{24}
=-5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*12}=\frac{24}{24}
=1
$