-5(2x+4)=10(-x-2)

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Solution for -5(2x+4)=10(-x-2) equation: 



-5(2x+4)=10(-x-2)

We move all terms to the left:

-5(2x+4)-(10(-x-2))=0

We add all the numbers together, and all the variables

-5(2x+4)-(10(-1x-2))=0

We multiply parentheses

-10x-(10(-1x-2))-20=0



We calculate terms in parentheses: -(10(-1x-2)), so:

10(-1x-2)

We multiply parentheses

-10x-20

Back to the equation:

-(-10x-20)



We get rid of parentheses

-10x+10x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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