-5(2x-1)+4(3x-2)=-6(x+3)

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Solution for -5(2x-1)+4(3x-2)=-6(x+3) equation: 



-5(2x-1)+4(3x-2)=-6(x+3)

We move all terms to the left:

-5(2x-1)+4(3x-2)-(-6(x+3))=0

We multiply parentheses

-10x+12x-(-6(x+3))+5-8=0



We calculate terms in parentheses: -(-6(x+3)), so:

-6(x+3)

We multiply parentheses

-6x-18

Back to the equation:

-(-6x-18)



We add all the numbers together, and all the variables

2x-(-6x-18)-3=0

We get rid of parentheses

2x+6x+18-3=0

We add all the numbers together, and all the variables

8x+15=0

We move all terms containing x to the left, all other terms to the right

8x=-15

x=-15/8

x=-1+7/8

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