-5(2x-10)+8x=40

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Solution for -5(2x-10)+8x=40 equation:



-5(2x-10)+8x=40
We move all terms to the left:
-5(2x-10)+8x-(40)=0
We add all the numbers together, and all the variables
8x-5(2x-10)-40=0
We multiply parentheses
8x-10x+50-40=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5

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