-5(2x-10)+8x=40

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Solution for -5(2x-10)+8x=40 equation: 



-5(2x-10)+8x=40

We move all terms to the left:

-5(2x-10)+8x-(40)=0

We add all the numbers together, and all the variables

8x-5(2x-10)-40=0

We multiply parentheses

8x-10x+50-40=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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