-5(2x-3)=2(x-10)-37

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Solution for -5(2x-3)=2(x-10)-37 equation: 



-5(2x-3)=2(x-10)-37

We move all terms to the left:

-5(2x-3)-(2(x-10)-37)=0

We multiply parentheses

-10x-(2(x-10)-37)+15=0



We calculate terms in parentheses: -(2(x-10)-37), so:

2(x-10)-37

We multiply parentheses

2x-20-37

We add all the numbers together, and all the variables

2x-57

Back to the equation:

-(2x-57)



We get rid of parentheses

-10x-2x+57+15=0

We add all the numbers together, and all the variables

-12x+72=0

We move all terms containing x to the left, all other terms to the right

-12x=-72

x=-72/-12

x=+6

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