-5(2x-3)=2(x-2)-29

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Solution for -5(2x-3)=2(x-2)-29 equation: 



-5(2x-3)=2(x-2)-29

We move all terms to the left:

-5(2x-3)-(2(x-2)-29)=0

We multiply parentheses

-10x-(2(x-2)-29)+15=0



We calculate terms in parentheses: -(2(x-2)-29), so:

2(x-2)-29

We multiply parentheses

2x-4-29

We add all the numbers together, and all the variables

2x-33

Back to the equation:

-(2x-33)



We get rid of parentheses

-10x-2x+33+15=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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