-5(2x-3)=2(x-38)-5

Solution for -5(2x-3)=2(x-38)-5 equation:

-5(2x-3)=2(x-38)-5

We move all terms to the left:

-5(2x-3)-(2(x-38)-5)=0

We multiply parentheses

-10x-(2(x-38)-5)+15=0


We calculate terms in parentheses: -(2(x-38)-5), so:

2(x-38)-5

We multiply parentheses

2x-76-5

We add all the numbers together, and all the variables

2x-81

Back to the equation:

-(2x-81)


We get rid of parentheses

-10x-2x+81+15=0

We add all the numbers together, and all the variables

-12x+96=0

We move all terms containing x to the left, all other terms to the right

-12x=-96

x=-96/-12

x=+8