-5(2x-3)=2(x-40)-49

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Solution for -5(2x-3)=2(x-40)-49 equation: 



-5(2x-3)=2(x-40)-49

We move all terms to the left:

-5(2x-3)-(2(x-40)-49)=0

We multiply parentheses

-10x-(2(x-40)-49)+15=0



We calculate terms in parentheses: -(2(x-40)-49), so:

2(x-40)-49

We multiply parentheses

2x-80-49

We add all the numbers together, and all the variables

2x-129

Back to the equation:

-(2x-129)



We get rid of parentheses

-10x-2x+129+15=0

We add all the numbers together, and all the variables

-12x+144=0

We move all terms containing x to the left, all other terms to the right

-12x=-144

x=-144/-12

x=+12

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