-5(2x-5)=2(x-10)-27

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Solution for -5(2x-5)=2(x-10)-27 equation:



-5(2x-5)=2(x-10)-27
We move all terms to the left:
-5(2x-5)-(2(x-10)-27)=0
We multiply parentheses
-10x-(2(x-10)-27)+25=0
We calculate terms in parentheses: -(2(x-10)-27), so:
2(x-10)-27
We multiply parentheses
2x-20-27
We add all the numbers together, and all the variables
2x-47
Back to the equation:
-(2x-47)
We get rid of parentheses
-10x-2x+47+25=0
We add all the numbers together, and all the variables
-12x+72=0
We move all terms containing x to the left, all other terms to the right
-12x=-72
x=-72/-12
x=+6

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