-5(2x-5)=2(x-2)-19

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Solution for -5(2x-5)=2(x-2)-19 equation:



-5(2x-5)=2(x-2)-19
We move all terms to the left:
-5(2x-5)-(2(x-2)-19)=0
We multiply parentheses
-10x-(2(x-2)-19)+25=0
We calculate terms in parentheses: -(2(x-2)-19), so:
2(x-2)-19
We multiply parentheses
2x-4-19
We add all the numbers together, and all the variables
2x-23
Back to the equation:
-(2x-23)
We get rid of parentheses
-10x-2x+23+25=0
We add all the numbers together, and all the variables
-12x+48=0
We move all terms containing x to the left, all other terms to the right
-12x=-48
x=-48/-12
x=+4

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