-5(2x-5)=2(x-44)-31

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Solution for -5(2x-5)=2(x-44)-31 equation: 



-5(2x-5)=2(x-44)-31

We move all terms to the left:

-5(2x-5)-(2(x-44)-31)=0

We multiply parentheses

-10x-(2(x-44)-31)+25=0



We calculate terms in parentheses: -(2(x-44)-31), so:

2(x-44)-31

We multiply parentheses

2x-88-31

We add all the numbers together, and all the variables

2x-119

Back to the equation:

-(2x-119)



We get rid of parentheses

-10x-2x+119+25=0

We add all the numbers together, and all the variables

-12x+144=0

We move all terms containing x to the left, all other terms to the right

-12x=-144

x=-144/-12

x=+12

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