-5(2x-5)=5-2(4x-2)

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Solution for -5(2x-5)=5-2(4x-2) equation: 



-5(2x-5)=5-2(4x-2)

We move all terms to the left:

-5(2x-5)-(5-2(4x-2))=0

We multiply parentheses

-10x-(5-2(4x-2))+25=0



We calculate terms in parentheses: -(5-2(4x-2)), so:

5-2(4x-2)

determiningTheFunctionDomain
-2(4x-2)+5

We multiply parentheses

-8x+4+5

We add all the numbers together, and all the variables

-8x+9

Back to the equation:

-(-8x+9)



We get rid of parentheses

-10x+8x-9+25=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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