-5(2x-6)+8(3x-7)=8(x-9)+12x

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Solution for -5(2x-6)+8(3x-7)=8(x-9)+12x equation: 



-5(2x-6)+8(3x-7)=8(x-9)+12x

We move all terms to the left:

-5(2x-6)+8(3x-7)-(8(x-9)+12x)=0

We multiply parentheses

-10x+24x-(8(x-9)+12x)+30-56=0



We calculate terms in parentheses: -(8(x-9)+12x), so:

8(x-9)+12x

We add all the numbers together, and all the variables

12x+8(x-9)

We multiply parentheses

12x+8x-72

We add all the numbers together, and all the variables

20x-72

Back to the equation:

-(20x-72)



We add all the numbers together, and all the variables

14x-(20x-72)-26=0

We get rid of parentheses

14x-20x+72-26=0

We add all the numbers together, and all the variables

-6x+46=0

We move all terms containing x to the left, all other terms to the right

-6x=-46

x=-46/-6

x=7+2/3

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