-5(2y+2)-20=-8(y+5)+2y

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Solution for -5(2y+2)-20=-8(y+5)+2y equation:



-5(2y+2)-20=-8(y+5)+2y
We move all terms to the left:
-5(2y+2)-20-(-8(y+5)+2y)=0
We multiply parentheses
-10y-(-8(y+5)+2y)-10-20=0
We calculate terms in parentheses: -(-8(y+5)+2y), so:
-8(y+5)+2y
We add all the numbers together, and all the variables
2y-8(y+5)
We multiply parentheses
2y-8y-40
We add all the numbers together, and all the variables
-6y-40
Back to the equation:
-(-6y-40)
We add all the numbers together, and all the variables
-10y-(-6y-40)-30=0
We get rid of parentheses
-10y+6y+40-30=0
We add all the numbers together, and all the variables
-4y+10=0
We move all terms containing y to the left, all other terms to the right
-4y=-10
y=-10/-4
y=2+1/2

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