-5(2y+3)+3=(4y-1)

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Solution for -5(2y+3)+3=(4y-1) equation: 



-5(2y+3)+3=(4y-1)

We move all terms to the left:

-5(2y+3)+3-((4y-1))=0

We multiply parentheses

-10y-((4y-1))-15+3=0



We calculate terms in parentheses: -((4y-1)), so:

(4y-1)

We get rid of parentheses

4y-1

Back to the equation:

-(4y-1)



We add all the numbers together, and all the variables

-10y-(4y-1)-12=0

We get rid of parentheses

-10y-4y+1-12=0

We add all the numbers together, and all the variables

-14y-11=0

We move all terms containing y to the left, all other terms to the right

-14y=11

y=11/-14

y=-11/14

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