-5(2y+3)-19=-8(y+5)+2y

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Solution for -5(2y+3)-19=-8(y+5)+2y equation: 



-5(2y+3)-19=-8(y+5)+2y

We move all terms to the left:

-5(2y+3)-19-(-8(y+5)+2y)=0

We multiply parentheses

-10y-(-8(y+5)+2y)-15-19=0



We calculate terms in parentheses: -(-8(y+5)+2y), so:

-8(y+5)+2y

We add all the numbers together, and all the variables

2y-8(y+5)

We multiply parentheses

2y-8y-40

We add all the numbers together, and all the variables

-6y-40

Back to the equation:

-(-6y-40)



We add all the numbers together, and all the variables

-10y-(-6y-40)-34=0

We get rid of parentheses

-10y+6y+40-34=0

We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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