-5(2y-2)-y=-3(y-2)

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Solution for -5(2y-2)-y=-3(y-2) equation: 



-5(2y-2)-y=-3(y-2)

We move all terms to the left:

-5(2y-2)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-5(2y-2)-(-3(y-2))=0

We multiply parentheses

-1y-10y-(-3(y-2))+10=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-11y-(-3y+6)+10=0

We get rid of parentheses

-11y+3y-6+10=0

We add all the numbers together, and all the variables

-8y+4=0

We move all terms containing y to the left, all other terms to the right

-8y=-4

y=-4/-8

y=1/2

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