-5(2y-4)+6y=6(y+4)

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Solution for -5(2y-4)+6y=6(y+4) equation: 



-5(2y-4)+6y=6(y+4)

We move all terms to the left:

-5(2y-4)+6y-(6(y+4))=0

We add all the numbers together, and all the variables

6y-5(2y-4)-(6(y+4))=0

We multiply parentheses

6y-10y-(6(y+4))+20=0



We calculate terms in parentheses: -(6(y+4)), so:

6(y+4)

We multiply parentheses

6y+24

Back to the equation:

-(6y+24)



We add all the numbers together, and all the variables

-4y-(6y+24)+20=0

We get rid of parentheses

-4y-6y-24+20=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5

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