-5(2y-4)=2(2-5y)+16

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Solution for -5(2y-4)=2(2-5y)+16 equation: 



-5(2y-4)=2(2-5y)+16

We move all terms to the left:

-5(2y-4)-(2(2-5y)+16)=0

We add all the numbers together, and all the variables

-5(2y-4)-(2(-5y+2)+16)=0

We multiply parentheses

-10y-(2(-5y+2)+16)+20=0



We calculate terms in parentheses: -(2(-5y+2)+16), so:

2(-5y+2)+16

We multiply parentheses

-10y+4+16

We add all the numbers together, and all the variables

-10y+20

Back to the equation:

-(-10y+20)



We get rid of parentheses

-10y+10y-20+20=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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