-5(3+2r)=-4r-6(2+r)-3

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Solution for -5(3+2r)=-4r-6(2+r)-3 equation: 



-5(3+2r)=-4r-6(2+r)-3

We move all terms to the left:

-5(3+2r)-(-4r-6(2+r)-3)=0

We add all the numbers together, and all the variables

-5(2r+3)-(-4r-6(r+2)-3)=0

We multiply parentheses

-10r-(-4r-6(r+2)-3)-15=0



We calculate terms in parentheses: -(-4r-6(r+2)-3), so:

-4r-6(r+2)-3

We multiply parentheses

-4r-6r-12-3

We add all the numbers together, and all the variables

-10r-15

Back to the equation:

-(-10r-15)



We get rid of parentheses

-10r+10r+15-15=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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