-5(3-k)-3=3(k-2)

Solution for -5(3-k)-3=3(k-2) equation:

-5(3-k)-3=3(k-2)

We move all terms to the left:

-5(3-k)-3-(3(k-2))=0

We add all the numbers together, and all the variables

-5(-1k+3)-(3(k-2))-3=0

We multiply parentheses

5k-(3(k-2))-15-3=0


We calculate terms in parentheses: -(3(k-2)), so:

3(k-2)

We multiply parentheses

3k-6

Back to the equation:

-(3k-6)


We add all the numbers together, and all the variables

5k-(3k-6)-18=0

We get rid of parentheses

5k-3k+6-18=0

We add all the numbers together, and all the variables

2k-12=0

We move all terms containing k to the left, all other terms to the right

2k=12

k=12/2

k=6