-5(36+12)=-36-5(b+12)

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Solution for -5(36+12)=-36-5(b+12) equation: 



-5(36+12)=-36-5(b+12)

We move all terms to the left:

-5(36+12)-(-36-5(b+12))=0

We add all the numbers together, and all the variables

-(-36-5(b+12))-548=0



We calculate terms in parentheses: -(-36-5(b+12)), so:

-36-5(b+12)

determiningTheFunctionDomain
-5(b+12)-36

We multiply parentheses

-5b-60-36

We add all the numbers together, and all the variables

-5b-96

Back to the equation:

-(-5b-96)



We get rid of parentheses

5b+96-548=0

We add all the numbers together, and all the variables

5b-452=0

We move all terms containing b to the left, all other terms to the right

5b=452

b=452/5

b=90+2/5

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